# 5x-3y=12 what is the x-intercept

## Related Questions

If you graph this function you can see that the parabola has an x-intercept at (8,0). This also happens to be the vertex and minimum as well.

2) x-intercept => y = 0 => factor the function (start by dividing by x -2)

f(x) = (x-2)(x-3)(x-6) =0 => x =2, x = 3, x = 6 (these are the x-intercepts)

3) critical points:

between x = 2 and x = 3, there is a local maximum

between x =3 and x = 6 there is a local minimum

3) Shape.

The function comes growing from - infinity.

In the third quadrant the function is negative (it does not pass throuhg the second quadrant)

It enters to the fourth quadrant intercepting the y-axis at y = -36. It continues growing and intercepts the x-axis at x = 2.

It continues increasing until a maximum local positive value, starts to decrease, intercepts the x-axis at x = 3, continues decreasing, becomes negative, gets a local minimum in the fourth quadrant, starts to increase, intercepts the x-axis at x = 6, becomes positive, and continues growing.

Literally 2 years late..

X-intercept = -3

Y-intercept = -6

1. -10x + 5y = 40

to find x-intercept set y=0

= -10x + 5(0) = 40 since 5(0) = 0

= -10x = 40 divide both sides by -10 to find X

=> x = 40/-10 = -4

=> the x-intercept for the above equation is -4

to find y-intercept set x = 0

= -10(0) + 5y = 40 since -10(0) = 0

= 0 + 5y = 40

=> 5y = 40 divide both sides by 5 to get the value of Y

=> y = 40/5 = 8

=> the y-intercept for the above equation is 8

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What are the x-intercept and y-intercept of the graph of y=1/3 x−6 x: Y:

Y: (0,-6)

The y intercept is in the equation

Find the x-intercepts of the parabola with vertex (-3,-18) and y-intercept at (0,0)

0 + 18 = a(0 + 3)^2

18 = 9a

2 = a

y = 2(x + 3)^2 - 18

0 = 2(x + 3)^2 - 18

18 = 2(x + 3)^2

9 = (x + 3)^2

± 3 = x + 3

-3 ± 3 = x

x = 0 or -6

(0, 0) and (-6, 0)

x-intercept, y = 0;

20x + 8(0) = 240

20x = 240

x = 240/20

x = 12

y-intercept, x = 0;

20(0) + 8y = 240

8y =240

y =240/8

y = 30

.................................................

15x + 3y = 270

x-intercept, y = 0;

15x + 3(0) = 270

15x = 270

x = 270/15

x = 18

y-intercept, x = 0;

15(0) + 3y = 270

3y = 270

y = 270/3

y = 90

....................................

y = 8x + 168

x-intercept, y = 0;

0 = 8x + 168

8x = -168

x = -168/8

x = -21

y-intercept, x = 0;

y = 8(0) + 168

y = 168

let x1 represent first x intercept and

let x2 represent second x intercept

Formula for finding average of x intercepts is logicaly:

Avg = (x1 + x2)/2

we want to find x1 and x2

4x^2 - 24x + 20 = 0

x^2 - 6x + 5 = 0

x1 = 5

x2 = 1

Avg = 3

What is the x-intercept of the line graphed below?

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How many x-intercepts are there in y = –3x2 + 4x + 4

–3x^2 + 4x + 4

–(3x^2 - 4x - 4)

–(3x + 2)(x - 2)

x=-2/3 or 2, which means that there are x intercepts, at -2/3 and 2.

What is the x-intercept and the y-intercept in 4x+2y=-2

x-intercept means y = 0, x = -1/2

y-intercept means x = 0, y = -1

u could also have 5x-3y-12=0 it'd be easier

What is the midpoint of the x-intercepts of f(x) = (x – 2)(x – 4)?

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Y = -2x - 3, provide the x-y coordinates of the y-intercept and the x-intercept. show your work.

**For y-intercept**

**For x-intercept**

**Answer:**

Option A

**Step-by-step explanation:**

The equation has x intecepts at -1 and -5.

Hence function would be of the form

a(x+1)(x+5) for some real a.

To find a, let us use y intercept

When x =0 we have y =a(1)(5)

y intercept is given as -30

i.e. 5a = -30

a=-6

So

f(x) = -6(x+1)(x+5)

Option A is the right answer.

-m=>decreasing

y=-5x-1

take x=0=>y=-1 y-int

1 is c and 2. is d

Which function has x-intercepts of 3 and 8 and contains the point (1,-2)

**Answer:**

the answer is y=-1/7 (x-3)(x-8)

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The ordered pair for an x-intercept has an x-value of 0 A.True or False

the correct answer is false

yintercept is where the line crosses the y axis or where x=0

to solve, set each to zero

xint

set y=0

0=-2x-6

add 2x both sides

2x=-6

divide 2

x=-3

xint is x=-3 or the point (-3,0)

yint

set x=0

y=-6

yint is (0,-6)

xint is x=-3 or (-3,0)

yint is y=-6 or (0,-6)

- 2r + 1/2y = 18

-2r + 1/2(0) = 18

-2r = 18

r = -18/2

r = -9

so the x int is (-9,0)

y intercept is the points where the line crosses the y axis or where x=0

xint,

set y=0

2x=-12

x=-6

xint is -6

yint,

set x=0

-3y=-12

y=4

yint is 4

C is answer

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**What does y = when x is -1 or**

**What does x = when y is 2**

So since the slope of the line is 2, we can assume that B and C must be the answers but since you want one answer we need to be more accurate.

The answer is C

Because when y = 0 x = -1 and when y = 2 x = 0

So since the slope of the line is 2, we can assume that B and C must be the answers but since you want one answer we need to be more accurate.

The answer is C

Because when y = 0 x = -1 and when y = 2 x = 0

How do we find x-intercept of rational function

**You can find the x intercept of the equation by setting the value of y to zero and solving the equation. Similarly you can solve the y intercept by setting the value of x to zero and solving the equation. Now while solving this rational function for intercepts if you face a situation where the value in the denominator is zero it implies that there is no intercept in that case as dividing something by zero is indeterminate.**

hope this helps.

but i dont know what r u asking