A 490 n (her weight due to gravity) woman is standing on bathroom scale. what is the woman's mass in kilograms
2.63 moles ( 58.69 g/mol ) = 154.35 g Nickel
Hope this answers the question. Have a nice day.
In 2004 astronomers reported the discovery of a large Jupiter-sized planet orbiting very close to the star HD 179949 (hence the term "hot Jupiter"). The orbit was just 19 the distance of Mercury from our sun, and it takes the planet only 3.09 days to make one orbit (assumed to be circular). What is the mass of the star? Express your answer (a)in kilograms and (b)as a multiple of our sun's mass.
Use Kepler's 3rd Law
T^2 = k R^3
where k = 4(pi)^2/ GM
G =gravitational constant = 6.67300 × 10-11 m3 kg-1 s-2
M = mass of this new planet
pi = 3.14159265
T =3.09 days = 266976 seconds
R = (579,000,000km)/9 = 64333333.3 km
Solve Kepler's 3rd Law for M. Your answer will be in kg
mass of the sun = 1.98892 × 10^30 kilograms
Form the ratio
Any beaker to measure the volume of liquid displaced
The stress force that causes a mass of rock to pull or twist in opposite directions is called shearing.
Hope this helps! :)
Planet a has three times the mass of planet b and the same radius. from this information, what can we conclude about the acceleration due to gravity at the surface of planet a compared to that at the surface of planet b?
Hence mass grows 3 times - g will grow 3 times as well
The acceleration of an object can be calculated by using Newton's second law:
F is the net force applied on the object
m is the mass of the object
a is its acceleration
In this problem, we have F=125 N and m=25.0 kg, so we can rearrange the equation to calculate the acceleration:
Please help! Find the tension in each cord in the figure if the weight of the suspended object is w = 210N A) Find the tension in the cord A for system (b). B) Find the tension in the cord B for system (b).
- T a * cos 60° + T b * sin 45° - 210 N = 0
- T a * sin 60° + Tb cos 45° = 0
- 1/2 T a + √2 / 2 T b = 210 N
- √3 / 2 T a + √ 2 / 2 T b = 0 / * ( - 1 )
- 1/2 T a + √2 / 2 T b = 210 N
√ 3 / 2 T a - √2 / 2 T b = 0
T a ( √3 / 2 - 1 / 2 ) = 210 N
0.366 T a = 210 N
T a = 210 N : 0.366
1 ) T a = 573.77 N
Ta * √3 / 2 = T b * √ 2 / 2
T b = ( 573.77 * 1.732 ) : 1.4142
2 ) T b = 702.7 N
Two wagons of equal mass are filled with an equal mass of bricks. Person A pushes one wagon with twice the force that Person B pushes the second wagon. How is the acceleration affected? A. Person A's wagon will accelerate at twice the rate of Person B"s wagon. B. Person A's wagon will accelerate at 1/2 the rate of Person B's wagon. C. Both wagons will accelerate at the same rate, since the mass is the same.
Force times Mass equals Acceleration.
The answer is TRUE.
If the mass increases the number on the left side of the equation increases, thus increasing the right side as well.
Answer: The atomic mass of the platinum will be 195.
We know that,
Atomic mass is the sum of the electrons and protons.
Platinum is the chemical element and it is the symbol is Pt. The atomic number of the platinum is 78 and the atomic mass is the 195,084 u.
According to the question,
Rounded to the nearest whole number
Hence, The atomic mass of the platinum will be 195.
he gave the correct answer its just we had options when we were doing this assignment so thanks for going in depth
Which scenario relates to Mayer and Salovey’s third component of emotional intelligence (regulating emotions)? A. gauging a friend’s anxiety in the absence of verbal cues B. reacting pleasantly to a friend’s practical joke C. understanding a friend’s problems and providing support D. determining the underlying cause of a friend’s nervous breakdown E. asking for a friend’s suggestion when working through a conflict
Option C i.e understanding a friend's problems and providing support is the correct answer.
Mayer and Salovey’s third component of emotional intelligence (regulating emotions) is the ability to Understand Emotions. So understanding a friend’s problems and providing support is the scenario relates to Mayer and Salovey’s third component of emotional intelligence (regulating emotions)
What information does the atomic mass of an element provide? A. the sum of electrons and protons in an atom B. the difference between the number of protons and electrons C. the number of protons and neutrons in an atom D. the number of isotopes
The atomic mass is the sum of the number of neutrons and protons.
A student hangs a mass of 150 g on a force table at an angle of 150 degrees . If she then hangs a mass of 220 g at 270 degrees. A) at what angle should she hang a mass of 195 g so that the ring is in equilibrium? B) Draw the vectors
cosΘ = 0.666
Θ = ± 48º
150g*sin150 + 220g*sin270 + 195g*sinΘ = 0
sinΘ = 0.744
Θ = 48º
1. Which of the following is NOT part of John Dalton's atomic theory? A. All elements are composed of atoms. B. All atoms of the same element have the same mass. C. Atoms contain subatomic particles. D. A compound contains atoms of more more than one element. 2. Who provided evidence for the existence of a nucleus in an atom? A. John Dalton B. J. J Thomson C. Democritus D. Ernest Rutherford
His theory did not incorporate the existence of subatomic particles.
The gravitation force of attraction between the two bodies is directly proportional tp the product of masses of two bodies and inversely proportional to the square of distance between them.
I Think It Is Wave And BioMass
An athlete is working out in the weight room. He steadily holds 50 kilograms above his head for 10 seconds. Which statement is true about this situation? The athlete isn’t doing any work because he doesn’t move the weight. The athlete isn’t doing any work because he doesn’t hold the weight long enough. The athlete is doing work because he prevents the weight from falling downward. The athlete is doing work because 50 kilograms is a significant load to lift.
But if he passed high school physics, then he may remember that
'work' in physics means (force) x (distance). If there's no distance,
then there's no work.
He realizes that he isn’t doing any work because he's not moving the weight.
A sled and rider, gliding over horizontal, frictionless ice at 4.7 m/s , have a combined mass of 80 kg . The sled then slides over a rough spot in the ice, slowing down to 3.4 m/s . What impulse was delivered to the sled by the friction force from the rough spot? Express your answer to two significant figures and include the appropriate units.
All we need is the momentum before and after.
Momentum = (mass) x (speed)
Before: = (80 kg) x (4.7 m/s) = 376 kg-m/s
After: = (80 kg) x (3.4 m/s) = 272 kg-m/s
Change in momentum = (376 - 272) = 104 kg-m/s
Notice that when you work with impulse, you're USUALLY calculating
(force) x (time).
The force is in Newtons, and the time is in seconds,
so the impulse is usually in units of
So how can I say that impulse and change of momentum are
the same thing ? Am I trying to pull a fast one on you ?
Remember that 1 Newton is 1 kg-m/s²
So (force) x (time)
= (Newton) x (second)
= (kg-m/s²) x (second) = kg-m/s .
and Momentum = (mass) x (speed) = (kg) x (m/s)
The units of impulse are the same as the units of momentum !
So when you give an object some impulse, you give it exactly
that much momentum.