# An athlete is working out in the weight room. He steadily holds 50 kilograms above his head for 10 seconds. Which statement is true about this situation? The athlete isn’t doing any work because he doesn’t move the weight. The athlete isn’t doing any work because he doesn’t hold the weight long enough. The athlete is doing work because he prevents the weight from falling downward. The athlete is doing work because 50 kilograms is a significant load to lift.

But if he passed high school physics, then he may remember that

'work' in physics means (force) x (distance). If there's no distance,

then there's no work.

He realizes that he isn’t doing any work because he's not moving the weight.

## Related Questions

Use Kepler's 3rd Law

T^2 = k R^3

where k = 4(pi)^2/ GM

G =gravitational constant = 6.67300 × 10-11 m3 kg-1 s-2

M = mass of this new planet

pi = 3.14159265

T =3.09 days = 266976 seconds

R = (579,000,000km)/9 = 64333333.3 km

a)

Solve Kepler's 3rd Law for M. Your answer will be in kg

b)

mass of the sun = 1.98892 × 10^30 kilograms

Form the ratio

M(planet)/M(sun)

**Answer:**

Part a)

Part b)

**Explanation:**

Part a)

As we know that

here we know that

so we will have

Part b)

if finally the snowmobile comes to rest

So here we can say that

so now we have

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. How much work in joules is done by a person who uses a force of 25 N to move a desk 3.0 m?

here, F = 25 N

s = 3 m

Substitute it into the expression,

W = 25 * 3

W = 75 Joule

**So, your final answer is 75 J**

Hope this helps!

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When a falling object reaches terminal velocity, the net force acting on it is

Explain Why must a cooling system do work to transfer thermal energy?

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the answer is d i just took the test k 12 right

There are 2 ways of solving this question

First is to use formula which connects starting speed, acceleration (which we would calculate from graph where we can see how speed changes) and time to calculate traveled distance.

S = V0 * t + 1/2*a*t^2

acceleration a is a = -4m/s^2

S(t=3s) = 18

On this value we add 12 initial meters of distance and we get S(t=3s) = 30 meters

For t=4s we get

S = 16 m

Plus initial distance of 12 m we get 30 meters

Answers are 30 and 28 meters.

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second way is to find surface of graph bellow speed line for 3 and 4 seconds...

- T a * cos 60° + T b * sin 45° - 210 N = 0

- T a * sin 60° + Tb cos 45° = 0

------------------------------------------------------

- 1/2 T a + √2 / 2 T b = 210 N

- √3 / 2 T a + √ 2 / 2 T b = 0 / * ( - 1 )

---------------------------------------------------

- 1/2 T a + √2 / 2 T b = 210 N

√ 3 / 2 T a - √2 / 2 T b = 0

----------------------------------------

T a ( √3 / 2 - 1 / 2 ) = 210 N

0.366 T a = 210 N

T a = 210 N : 0.366

**1 )**

**T a = 573.77 N**

Ta * √3 / 2 = T b * √ 2 / 2

T b = ( 573.77 * 1.732 ) : 1.4142

**2 )**

**T b = 702.7 N**

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Force times Mass equals Acceleration.

**The answer is TRUE.**

If the mass increases the number on the left side of the equation increases, thus increasing the right side as well.

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The answer is D I just took the test on study island

and there is an explanation

**When crustal plates scrape and slide past one another, they release built-up energy. This energy travels through the Earth as earthquakes.**

What is meant by the following statement? "Acceleration is inversely proportional to mass."

**Answer:**

he gave the correct answer its just we had options when we were doing this assignment so thanks for going in depth

**Explanation:**

Ps Odsseyware

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Why doesn't an electromagnetic wave move as fast through a solid as it would a gas

(0.544881 mol C) × (12.01078 g C/mol) = 6.54445 g C

(4.91 g H2O) / (18.01532 g H2O/mol) × (2 mol H / 1 mol H2O) = 0.54509 mol H

(0.54509 mol H) × (1.007947 g H/mol) = 0.54942 g H

10 g total - 6.54445 g C - 0.54942 g H = 2.90613 g O

(2.90613 g O) / (15.99943 g O/mol) = 0.18164 mol O

Divide by the smallest number of moles:

(0.544881 mol C) / 0.18164 mol = 2.9998

(0.54509 mol H) / 0.18164 mol = 3.0009

(0.18164 mol O) / 0.18164 mol = 1.0000

Round to the nearest whole number to find the empirical formula:

C3H3O

**Option C i.e understanding a friend's problems and providing support is the correct answer.**

**Mayer and Salovey’s third component of emotional intelligence (regulating emotions) is the ability to Understand Emotions**. So understanding a friend’s problems and providing support is the scenario relates to Mayer and Salovey’s third component of emotional intelligence (regulating emotions)

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Emission lines occur only in the case of transitions from higher to lower energy levels in which energy is emitted.

The electromagnetic spectrum contains visible light along with many other components such as radio waves, microwaves, ultraviolet rays and gamma rays.

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cosΘ = 0.666

Θ = ± 48º

Vertically:

150g*sin150 + 220g*sin270 + 195g*sinΘ = 0

sinΘ = 0.744

Θ = 48º

E = nhc / λ

Also, Power = Energy / time

E = 20 x 10⁻³ x 60 x 60

E = 108 J

108 = (2.29 x 10²⁰ x 6.63 x 10⁻³⁴ x 3 x 10⁸) / λ

λ = 4.22 x 10⁻⁷ m

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