. How much work in joules is done by a person who uses a force of 25 N to move a desk 3.0 m?
here, F = 25 N
s = 3 m
Substitute it into the expression,
W = 25 * 3
W = 75 Joule
So, your final answer is 75 J
Hope this helps!
How would the acceleration of a chain of three shopping carts compare with the acceleration of a single cart if the same force acted on both? A. 1/3 as much the single B. 1/2 as much the single C. 3 times as much the single D. 2 times as much the single
a = F/m
a' = F/3m
a'/a = 1/3
Based on this, the correct answer would be option A.1/3 as much the single Hope this helps.
The stress force that causes a mass of rock to pull or twist in opposite directions is called shearing.
Hope this helps! :)
where Q is the energy lost,
c is the specific heat of water,
m is the mass of water involved,
so m=3.75 *10^-1 Kg
delta t=37.5 °C
I hope my answer has come to your help. God bless and have a nice day ahead!
SIZE AND DISTANCE BETWEEN THEM
F = 49N
I Took The Test!
The acceleration of an object can be calculated by using Newton's second law:
F is the net force applied on the object
m is the mass of the object
a is its acceleration
In this problem, we have F=125 N and m=25.0 kg, so we can rearrange the equation to calculate the acceleration:
There are 2 ways of solving this question
First is to use formula which connects starting speed, acceleration (which we would calculate from graph where we can see how speed changes) and time to calculate traveled distance.
S = V0 * t + 1/2*a*t^2
acceleration a is a = -4m/s^2
S(t=3s) = 18
On this value we add 12 initial meters of distance and we get S(t=3s) = 30 meters
For t=4s we get
S = 16 m
Plus initial distance of 12 m we get 30 meters
Answers are 30 and 28 meters.
second way is to find surface of graph bellow speed line for 3 and 4 seconds...
Two wagons of equal mass are filled with an equal mass of bricks. Person A pushes one wagon with twice the force that Person B pushes the second wagon. How is the acceleration affected? A. Person A's wagon will accelerate at twice the rate of Person B"s wagon. B. Person A's wagon will accelerate at 1/2 the rate of Person B's wagon. C. Both wagons will accelerate at the same rate, since the mass is the same.
Force times Mass equals Acceleration.
The answer is TRUE.
If the mass increases the number on the left side of the equation increases, thus increasing the right side as well.
Which scenario relates to Mayer and Salovey’s third component of emotional intelligence (regulating emotions)? A. gauging a friend’s anxiety in the absence of verbal cues B. reacting pleasantly to a friend’s practical joke C. understanding a friend’s problems and providing support D. determining the underlying cause of a friend’s nervous breakdown E. asking for a friend’s suggestion when working through a conflict
Option C i.e understanding a friend's problems and providing support is the correct answer.
Mayer and Salovey’s third component of emotional intelligence (regulating emotions) is the ability to Understand Emotions. So understanding a friend’s problems and providing support is the scenario relates to Mayer and Salovey’s third component of emotional intelligence (regulating emotions)
What do the yellow arrows in this illustration represent? A. movement of earth’s tectonic plates B. convection in the asthenosphere C. convection in the lithosphere D. direction of earth's magnetic field
It is given that,
Mass of the meteor, m = 521 kg
Force acting on the meteor, F = 2520 N
Let a is the acceleration of the meteor. It can be calculated using the Newton's second law of motion. According to this law the force acting on an object is equal to the product of mass and acceleration with which it is moving. Mathematically, it is given by :
So, the acceleration of the meteor is . Hence, this is the required solution.
What happens when the electron moves from the first energy level to the second energy level? Energy is absorbed, and an emission line is produced. Energy is released, and an emission line is produced. Energy is absorbed by the atom. Energy is lost from the atom.
Emission lines occur only in the case of transitions from higher to lower energy levels in which energy is emitted.
A student hangs a mass of 150 g on a force table at an angle of 150 degrees . If she then hangs a mass of 220 g at 270 degrees. A) at what angle should she hang a mass of 195 g so that the ring is in equilibrium? B) Draw the vectors
cosΘ = 0.666
Θ = ± 48º
150g*sin150 + 220g*sin270 + 195g*sinΘ = 0
sinΘ = 0.744
Θ = 48º
Which of the following might be considered a viable application of a radioactive tracer? It can be more then one? A) adding a stream of radioisotopes to waste water to examine where pollution goes when it flows into the ocean B) embedding a radioactive plug in a valuable necklace so that its location can be determined using a Geiger counter C) placing radioactive sources around a room to trace the location of people as they move through the room d.) filling a pipeline with radioactive gas to see if it contains any leaks
B. Greater energy
Fast moving water is very energetic as its can displace very large rocks, boulders and make pebbles and sand out of them through the process r erosion. Fast moving water have kinetic energy, it opposes anything that come in its way. As river make its own channel by eroding plane. Many antecedent rivers have make their channel by cutting large mountains too.
A gas has an initial volume of 212 cm^3 at a temperature of 293 K and a pressure of 0.98 atm. What is the final pressure of the gas if the volume decreases to 196 cm^3 and the temperature of the gas increases to 308 K? a. 0.86 atm b. 0.95 atm c. 1.0 atm d. 1.1 atm
P1V1/T1 = P2V2/T2
in this equation we know:
P1,V1 and T1, T2 and V2.
We have one equation and 1 unknown variable.
P2 = T2P1V1/T1V2 = 1.1atm
The space shuttle travels at about 28,000 km per hour. Using that information, estimate how many hours it will take the shuttle to reach Saturn from Earth. Show your work. Convert your answer into scientific notation if necessary.
s = 1 275 000 000 km
The time required to travel that distance is:
t = s/v = 45535 hours or 1897.3 days
A football is kicked into the air from an initial height of 4 feet. The height, in feet, of the football above the ground is given by ￼s (t)=-16^2+50t+4, where t is time, in seconds, and t>=0. At what time will the football be 25 feet above the ground? 3.625 seconds 3.20 seconds 0.5 seconds or 3.625 seconds 0.5 seconds or 2.625 seconds
Answer: 0.5 seconds or 2.625 seconds
At t = 0, The ball is 4 ft above the ground.
The height of the football varies with time in the following way:
s(t) = -16 t² + 50 t + 4
we need to find the time in which the height would of the football would be 25 ft:
⇒25 = -16 t² + 50 t + 4
we need to solve the quadratic equation:
⇒ 16 t² - 50 t + 21 = 0
⇒ t = 0.5 s or 2.625 s
Therefore, at t = 0.5 s or 2.625 s, the football would be 25 ft above the ground.
When an electric current is passed through water during the process of electrolysis, two gases are formed. One gas has a boiling point of -183 degrees celsius and the other has a boiling point of -253 degrees celsius. Has a physical change or a chemical change occurred? Explain.
The gravitation force of attraction between the two bodies is directly proportional tp the product of masses of two bodies and inversely proportional to the square of distance between them.