In a transverse wave the peak of the wave is the crest and the lowest spot is the trough
If something is missing, then put it please otherwise no-one can help you!
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PLEASE HELP FAST??!! Which statement is true about the electromagnetic spectrum? A. The visible Spectrum includes radio waves, light and gamma rays. B. Same wave lengths of light corresponding to different colors. C. It contains a spectrum of visible light plus a wide array of nonvisible forms of radiation. D. The waves travel at a speed of 2.998 *10^5 m/s
The electromagnetic spectrum contains visible light along with many other components such as radio waves, microwaves, ultraviolet rays and gamma rays.
E = nhc / λ
Also, Power = Energy / time
E = 20 x 10⁻³ x 60 x 60
E = 108 J
108 = (2.29 x 10²⁰ x 6.63 x 10⁻³⁴ x 3 x 10⁸) / λ
λ = 4.22 x 10⁻⁷ m
I Think It Is Wave And BioMass
A sled and rider, gliding over horizontal, frictionless ice at 4.7 m/s , have a combined mass of 80 kg . The sled then slides over a rough spot in the ice, slowing down to 3.4 m/s . What impulse was delivered to the sled by the friction force from the rough spot? Express your answer to two significant figures and include the appropriate units.
All we need is the momentum before and after.
Momentum = (mass) x (speed)
Before: = (80 kg) x (4.7 m/s) = 376 kg-m/s
After: = (80 kg) x (3.4 m/s) = 272 kg-m/s
Change in momentum = (376 - 272) = 104 kg-m/s
Notice that when you work with impulse, you're USUALLY calculating
(force) x (time).
The force is in Newtons, and the time is in seconds,
so the impulse is usually in units of
So how can I say that impulse and change of momentum are
the same thing ? Am I trying to pull a fast one on you ?
Remember that 1 Newton is 1 kg-m/s²
So (force) x (time)
= (Newton) x (second)
= (kg-m/s²) x (second) = kg-m/s .
and Momentum = (mass) x (speed) = (kg) x (m/s)
The units of impulse are the same as the units of momentum !
So when you give an object some impulse, you give it exactly
that much momentum.
Which one of the following scenarios accurately describes a condition in which resonance can occur?End of exam A. A person is holding a tuning fork on one end of a football field and another person is holding a separate tuning fork on the opposite end of the field. B. A pipe's length is equal to 1∕2 of the wavelength of the sound waves produced by a tuning fork vibrating over one end of the pipe that's open to the air at both ends.C. A vibrating tuning fork is struck and begins to vibrate as the object used to strike it is placed away from the tuning fork. D. A column of air has a height equal to 1∕8 of the wavelength of the sound waves produced by a tuning fork vibrating over the column of air in an open pipe that's partially immersed in water.
Answer: The correct answer is pulses.
Wave is a disturbance which carries energy from one particle to another. Wave is a continuous disturbance.
Pulse is a single disturbance. It travels through one point to another.
Sound wave consists of rarefaction and compression. It need medium to travel.
In the circular wave, the particles move both parallel and perpendicular to the motion of the wave.
Therefore, all waves consist of a continuous series of the pulses.
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Kelvin 0 is Absolute Zero, the atoms cannot physically become any closer.
The correct answer is reflection
I just took the test
The correct answer is B. Rock samples
To the kid in the comment section of the other. Thanks to you, I got it wrong.
Microwave ovens emit microwave energy with a wavelength of 12.5 cm. What is the energy of exactly one photon of this microwave radiation? I'm on sapling and I did it couple times, but I kept getting it wrong!!! I followed all the notes I have from lecture, can someone please help thank you
The energy of exactly one photon of this microwave radiation is .
Planck’s equation used to solve this question. In the Planck’s equation, the energy of a photon is directly related to the frequency of a photon and inversely related to the wavelength of a photon.
By using Planck’s equation the energy of the one photon can be determined.
The term “Electromagnetic wave radiation energy” was first introduced by the scientist Max Planck.
The light can travel very fast as in the no other thing can travel as faster as light and it’s measures value is approximate in vacuum.
The wavelength is the defined as the distance between two consecutive positive peak pointornegative peak point of the wave.
The wavelength of the energy is .
The expression for the energy of photon is:
Here, is the energy of photon, is the Plank constant, is the speed of the light and is the wavelength of the photon.
The value of the Plank constant is .
The value of the speed of the light is .
Substitute for , for and for in the above equation.
Therefore, the energy of exactly one photon of this microwave radiation is
1. The threshold frequency of the cesium brainly.com/question/6953278
2. The direction of propagation of a sound wave brainly.com/question/3619541
Grade: High School
Chapter: Photoelectric effect
The energy, photon, microwave, radiation, emits, wavelength ,12.5 cm or 0.125 m, 1.59x10^-23 J, speed of light, emission, Plank's constant.
∧ = Rh [ni - nf]
∧ = Rh [1/3-1/5]
∧ = Rh 2/15
So, your final answer is Rh * 2/15
Where, Rh = Rydberg's constant
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So, option B is your answer
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Your boss asks you to adjust the temperature so that a sound wave travels more quickly through the air you increase the temperature from 30 c to 36 c what's the velocity of the sound wave at this new temperature
initial speed of sound at 30 degree C
final speed of sound at 36 degree C
As we know that velocity of the sound in air is given by the formula as
here we know that
t = temperature or air in degree celcius
so here at 30 degree celcius we can say that
now at 36 degree C the speed of sound is given as
Put these greenhouse effect events in order, starting with light's origin. 1. Visible and shortwave radiation heat Earth 2. Earth radiates longwave radiation 3. Longwave radiation is reflected downward 4.. Longwave radiation heats Earth
A fellow student with a mathematical bent tells you that the wave function of a traveling wave on a thin rope is y(x,t)= 2.30mmcos[(6.98rad/m)x + (742 rad/s)t]. Being more practical, you measure the rope to have a length of 1.35 m and a mass of 0.00338 kg. You are then asked to determine the following: A) Amplitude B) Frequency C) Wavelength D) Wave Speed E) Direction the wave is traveling F) Tension in the rope G) Average power transmitted by the wave
A) Amplitude is 2.30mm
B) Frequency 1/2.30mm
C) Wavelength is 6.98rad/m
D) Wave Speed is 742 rad/s
E) Direction the wave is traveling
The energy gaps between the valence and conduction bands are called band gaps. For silicon, the band gap is 1.1 eV; for fused silica glass, it is 9.3 eV. What is the wavelength λ of a photon that has energy 1.1eV? The cut off between visible and infrared light is usually said to be somewhere between 700 and 800nm. Why is silicon transparent to most infrared light but opaque to visible light? a) Visible photons have greater energy than the gap, so they can be absorbed whereas infrared photons pass through. b) Visible photons have greater energy than the gap, so they can’t interact with the silicon as the infrared photons can. c) Infrared photons have less energy than the gap, and so, unlike visible photons, they can be absorbed and reemitted from the material. d) Infrared photons have less energy than the gap, and so they are only partially absorbed whereas visible photons are fully absorbed.
d) Infrared photons have less energy than the gap, and so they are only partially absorbed whereas visible photons are fully absorbed.
A widow's peak is a V-shaped area of the hairline in the center of the forehead. The allele for having a widow's peak is dominant to the allele for not having a widow's peak. If two parents do not have widow's peaks, what is the probability that their child will have a widow's peak? A. 75% B. 0% C. 25% D. 50%
A widow's peak is a V-shaped point in the hairline in the center of the forehead. Hair growth on the forehead is suppressed in a bilateral pair of periorbital fields. Without a widow's peak, these fields join in the middle of the forehead so as to give a hairline that runs straight across.