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# Solve this problem for x and y 8x+4y=-12 and -9x+4y=-29

The input: {8(+4)y=12,-9(+4)y=29

Result: {32y=12,-36y=29}

## Related Questions

Posted in Mathematics

Solve the equation for y 2x+6y=13

So here is how we are going to solve for y for the given equation above:
2x+6y=13
Next, transfer 2x to the right side and it will look like this:
6y=13-2x
Now, divide both sides by 6, and it will look like this:
y=13-2x
--------
6
So, this is the final answer for y.

Posted in Mathematics

How to solve this problem 14-6= 10-6=?

I really don't think you wrote the question properly. Or maybe you did, but this question doesn't make any sense! :/

Posted in Mathematics

Let P be a point between points S and T on 2004-01-01-02-00_files/i0120000.jpg. If ST = 21, SP = 3b – 11, and PT = b + 4, solve for b. A. –7 B. 7 C. 14 D. 32

The best and most correct answer among the choices provided by your question is the third choice or letter C.

If ST = 21, SP = 3b – 11, and PT = b + 4, the value of b would be 14.

I hope my answer has come to your help. God bless and have a nice day ahead!

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Posted in Mathematics

Solve the inequality. y – 5 ≥ 11

Y - 5 ≥ 11

Add 5 to the both sides,

y - 5 + 5 ≥ 11 + 5

y ≥ 16

Hope this helps!

Posted in Mathematics

Solve the inequality. p – 9 < –9

I hope this helps you

p-9 < -9

p-9+9 < -9+9

p <0

Posted in Mathematics

Solve for x. round to nearest tenth if needed. 1. 7r-7=2r+18 a.r=-5 b.r=5 c.r=2.2 d.r=1.2 2. 2x+12=18-x a.x=3 b.x=10 c.x=6 d.x=2 3. 8x-3=15x+18 a.x=-3 b.x=3 c.x=2.1 d.x=0.9 4. 6y-6=4y+16 a.y=2.2 b.y=-2.2 c.y=11 d.y=5 5. 3(x-4)=5(x+2) a.x=11 b.x=-11 c.x=1 d.x=-1

1)  The answer is: [B]: r = 5 .
__________________________
Explanation:
__________________________
Given: 7r − 7 = 2r + 18 ; Round your answer to the nearest tenth, if necessary.
____________________________
Since "r" is the only variable given, let us assume we want to solve for "r" (instead of "x").
___________________________
→ Subtract "2r" from EACH SIDE of the equation; and & add "7" to EACH SIDE of the equation:
_____________
→ 7r − 7 − 2r + 7 = 2r + 18 − 2r + 7 ;  to get: → 5r = 25 ;
_____________
→ Now, divide EACH SIDE of the equation by "5"; to isolate "r" on one side of the equation; and to solve for "r" :
______________
→ 5r / 5 = 25 / 5 → r = 5 → which is: "Answer choice: [B]".
_________________
Let us check our answer, by plugging in "5" for "r" in the original equation:
_________________
→ 7r − 7 = 2r + 18 ;  →  7(5) − 7 =? 2(5) + 18? ;
______________________
→ 35 − 7 =? 10 + 18 ?;     → 28 =? 28? Yes!
______________________
2) The answer is: [D]: x = 2 .
_____________
Explanation:
_____________
Given: 2x + 12 = 18 − x ; Solve for "x" (round to nearest tenth, if necessary).
_______________
→ Add "x" to EACH SIDE of the equation, & subtract "12" from EACH SIDE of the equation:  → 2x + 12 + x − 12 = 18 − x + x − 12 ;
______________
→ To get: 3x = 6 ;  → Divide EACH SIDE of the equation by "3";
to isolate "x" on one side of the equation; and to solve for "x":
_____________
→ 3x / 3 = 6 / 3 ; → x = 2 ; which is: "Answer choice: [D]".
______________
Let us check our answer, by plugging in "2" for "x" in the original equation:
________________
→ 2x + 12 = 18 − x ; → 2(2) + 12 =? 18 − 2 ?
________________
→ 4 + 12 =? 18 − 2 ? ;   → 16 =? 16?  Yes!
________________________________
3)  The answer is: [A]: x = -3 .
_____________
Explanation:
________________
Given:  8x − 3 = 15x + 18 ; Solve for "x". Round your answer to the nearest tenth, if necessary.
_________________
→ Subtract "8x" from EACH SIDE of the equation, & add "3" to EACH SIDE of the equation:
_______________
→ 8x − 3 − 8x + 3 = 15x + 18 − 8x + 3 ; to get:
_______________
→ 0 = 7x + 21 ; → Subtract "21" from EACH SIDE of the equation;
_______________
→ 0 − 21 = 7x + 21 − 21 ; to get:
_______________
→  -21 = 7x ; Now divide EACH SIDE of the equation by "7";
to isolate "x" on one side of the equation; & to solve for "x":
_______________
→ = -21 / 7 = 7x / 7 ; →  -3 = x ; which is "Answer choice: [A]."
_________________
Let us check our answer, by plugging in "-3" for "x" in the original equation:
________________
→  8x − 3 = 15x + 18 ;  → 8(-3) − 3 =?  15(-3) + 18 ?;
________________________
→ -24 − 3 =?  -45 + 18 ? ;   →  -27 =? -27?  Yes!
___________________________
4)  The answer is: [C]: y = 11 .
_____________
Explanation:
____________
Given: 6y − 6 = 4y + 16 ; Solve for "y"; Round to the nearest tenth, if necessary.
____________
(Note: Since "y" is the only variable given; assume we are to solve for "y" instead of "x").
____________
→ Subtract "4y" from EACH SIDE of the equation, & add "6" to EACH SIDE of the equation; → 6y − 6 − 4y + 6 = 4y + 16 − 4y + 6 ; to get:
_______________
→ 2y  = 22 ; Now, divide EACH SIDE of the equation by "2"; to isolate "y" one side of the equation; and to solve for "y" ;
_______________
→ 2y / 2 = 22 / 2 ; →  y = 11 → which is "Answer choice: [C]".
_______________________________
Let us check our answer, by plugging in "11" for "y" in the original equation:
___________________
→  6y − 6 = 4y + 16 ; → 6(11) − 6 =? 4(11) + 16 ?
_______________________
→ 66 − 6  =? 44 + 16 ?  → 60 =? 60 ?  Yes!
__________________
5)  The answer is: [B]: x = -11 .
_____________________
Explanation:
_________________
Given: 3(x − 4) = 5(x + 2) ; Solve for "x". Round to the nearest tenth, if necessary.
___________
→Note the "distributive property of multiplication":
_____________
a*(b + c) = ab + ac ;  and: a*(b − c) = ab − ac ;
_______________
→ Let us expand EACH SIDE of our given equation.
____________
3(x − 4) = (3*x)  − (3*4) = 3x − 12;
______________________________
→Now let us expand the "right-hand side" of the given equation:
____________
→  5(x + 2) = (5*x) + (5*2) = 5x + 10 ;
______________
→Now, we can rewrite the original equation:
_______________
→ 3(x − 4) = 5(x + 2) ; by substituting the expanded values for EACH SIDE of the question:   →  3x − 12 = 5x + 10 ;
__________________
→ Subtract "3x" from EACH SIDE of the equation; and add "12" to EACH SIDE of the equation: →  3x − 12 − 3x + 12 = 5x + 10 − 3x + 12 ; to get:
________________
→  0 = 2x + 22;  → Now subtract "22" from EACH SIDE of the equation:
______________
→  0 − 22 = 2x + 22 − 22 ; to get:  →  -22 = 2x ;
__________
→ Divide EACH SIDE of the equation by "2"; to isolate "x" on one side of the equation; & to solve for "x" ;
_____________
→  -22 / 2 = 2x /2 ;  →  -11 = x ; which is "Answer choice: [B]".
______________
Let us check our answer, by plugging in "-11" for "x" in the original equation:
___________
→ 3(x − 4) = 5(x + 2) ; →  3(-11 − 4) =? 5(-11 + 2) ? ;
_______________________
→3(-15) =? 5(-9) ? ; → -45 =? -45 ?  Yes!
_____________________________________________

Posted in Mathematics

So we have an equation:
2w=12-4w
Firstly, let's simplify, and divide all terms by 2:
w=6-2w
Now, we add 2w over to the other side:
3w=6
And finally, we divide both sides by 3:
w=2
Hope this helps!

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Posted in Mathematics

K-X=V-W solve for the letter x

-X = (V - W) - K

Mul -1 X = -(V-W) + K

X = -V + W + K

Posted in Mathematics

How can you solve 0.01×30

You can just do 1x30 which equals 30

Posted in Mathematics

200x50 mathematics problem

200*50=10,000.
2*5=10
20*50=1000
200*50=10000

Posted in Mathematics

How was percent used to solve real-world problems

A. When your teacher grades a test, s/he will give you percents (Ex: 99%, 87%...)
B. On Black Fridays, it would say 50% off, 30% off...

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Posted in Mathematics

Solve the proportion 15t/5=2t +3 /6.

15t/5=2t +3 /6
3t = 2t + 1/2
3t-2t = 1/2
t = 1/2

Hope this helps!

Posted in Mathematics

You would have to add up the total participants in the survey first. So, 30+35+40+25+10=140. Now, you would take the number of people under 17 (30) and divide it by the total participants (140). 30/140=21.4%. Hope this helps.

Ok, so when you're reading the bar graph, you can tell how many participants are in each group by looking at the y-axis. For example, there are 30 people under 17. There are 35 people aged 18-24, etc. The numbers on the y-axis you add up. So 30 (for under 17)+35(for 18-24), etc. Now, a percentage is basically a proportion.  So the whole, which in this case is the total amount of people surveyed, will always be the denominator. Then the portion that we are trying to find, which in this case is the people surveyed under 17, will be the numerator. Hence, 30/140.

Posted in Mathematics

Solve cos^2x + 2cosx + 1 = 0 for x over the interval [0, 2pi ). Can someone please give me a step by step answer. I don't understand at all.

Cos²x+2cos x+1=0

We have to do a change of variable.

cos x=t

Then, we have the next square equation.

t²+2t+1=0

We solve this square equation:

t=[-2⁺₋√(4-4)]/2=-1
if cos x=t  then we have that:

cos x=-1
x=cos⁻¹ -1= π radians    or    180º.

Posted in Mathematics

What do I do to start this problem.for #4

Divide the 228 by 5 and you should get 45.6 or rounding, 46

So, there were 46 girls and 182 boys.

You can check by multiplying 46 by 5 and you will get 228

Hope this helped

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Posted in Mathematics

Solve for q: qrv + 11 = 30

The answer is 4 hours and 30 minutes because if you add 1 hour following another hour and repeating until you get to 10:00 you add 1 more hour but you still need so you add 1 hour and it's to much so you add 30 minutes. In conclusion the answer is 4 hours and 30 minutes. 6:30 + 30 = 7:00 + 4 hours = 11:00

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Posted in Mathematics

Solve the following system of equations 9x +2y=17

9(0)+2y=17
2y/2=17/2
y=8.5
9x+2(0)=17
9x/9=17/9
x=1.8

(1.8,8.5)

Posted in Mathematics

The population of Cambridge, Massachusetts, is 101,355. The population of Boston is 616,535. What is the population of the two cities altogether? Hana solved this problem. She said that the answer was 717,890. Which statement is correct?

Hana's statement is indeed the correct one. How I determined this answer:

The question asks you for the total populations of Cambridge, Massachusetts, and Boston, Massachusetts, altogether. That means you have to add the two given numbers together: 616,535 + 101,355 = 717,890. This, of course, is also what Hana did and got for the answer, therefore her statement is the correct one.

Hope I helped you! :)

Posted in Mathematics

Solve by elimination -3x+2y=10 -2x-y=-5

First you need to get two similar terms to eliminate, I'll do y:
-3x + 2y = 10
-4x - 2y= -10
And then you minus
x = 20
Now you can substitute x in to one of the equations to find y:
-60 + 2y = 10
+ 60
2y = 70
÷ 2
y = 35
So your values are y = 35 and x = 20. Hope this helps!

Posted in Mathematics

Solve by elimination x+y=7 x-y=9

The 1st thing you do is see if you have something that will cancel each other out which you do and it is Y so cancel those out and you combine like terms and get 2x=16 and then divide by 2 and get x=8. then you plug 8 in to your equation and get 8+y=7 and then subtract 8 from both sides and get y=-1. Your solutions are x=8 and y=-1. Hope this helps

Posted in Mathematics

1.5x-2<10 how do you solve this

5x - 2 < 10
+ 2
5x < 12
÷ 5
x < 2.4
Hope this helped!

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