## Related Questions

- T a * cos 60° + T b * sin 45° - 210 N = 0

- T a * sin 60° + Tb cos 45° = 0

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- 1/2 T a + √2 / 2 T b = 210 N

- √3 / 2 T a + √ 2 / 2 T b = 0 / * ( - 1 )

---------------------------------------------------

- 1/2 T a + √2 / 2 T b = 210 N

√ 3 / 2 T a - √2 / 2 T b = 0

----------------------------------------

T a ( √3 / 2 - 1 / 2 ) = 210 N

0.366 T a = 210 N

T a = 210 N : 0.366

**1 )**

**T a = 573.77 N**

Ta * √3 / 2 = T b * √ 2 / 2

T b = ( 573.77 * 1.732 ) : 1.4142

**2 )**

**T b = 702.7 N**

But if he passed high school physics, then he may remember that

'work' in physics means (force) x (distance). If there's no distance,

then there's no work.

He realizes that he isn’t doing any work because he's not moving the weight.

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*Force = Mass * Acceleration*.

**Answer:**

ITS NONE

**Explanation:**

This is in accordance to Newton's first law which states that an object at rest will remain at rest and an object in motion will remain in motion unless an external force acts on it. The force must be a resultant force.

Therefore, the force needed increases with the total weight of the cart as well as with the added mass in a linear manner.

Explanation:

Given that,

Force of gravity acting on the person, F = mg = 850 N

The roof is on the 20 degrees slope with the surface. We need to find the magnitude of normal force of the roof on the worker. It can be calculated as :

So, the normal force of the roof on the worker is 798.73 N. Hence, this is the required solution.

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If gravitational pull got three times stronger what happens to your weight?

it would be 32newtons

20 kg*1.6 m/s²=32 N

What is the approximate weight of a 20-kg cannonball on Earth? 2 N 20 N 196 N 1,960 N

**Answer:**

Weight of the cannonball, W = 196 N

**Explanation:**

Mass of the cannonball, m = 20 kg

We need to find its weight on earth. The weight of an object on the earth can be calculated by the product of mass and acceleration due to gravity as :

W = 196 N

**So, the weight of the cannonball on the Earth's surface is 196 N. Hence, this is the required solution.**

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What would be the weight of the moon if it were resting on the surface of the earth

The calculation of the gravitational force between two objects

refers to the distance between their centers.

The minimum possible distance between the Earth's and moon's

centers is the sum of their radii (radiuses).

Earth's radius . . . . . 6,360 km = 6.36 x 10⁶ meters

Moon's radius . . . . . 1,738 km = 1.738 x 10⁶ meters

Sum of their radii = 8.098 x 10⁶ meters

Also:

Earth's mass . . . . . 5.972 x 10²⁴ kg

Moon's mass . . . . . 7.348 x 10²² kg

and now we're ready to go !

Gravitational force =

G M₁ M₂ / R²

= (6.67 x 10⁻¹¹ N-m²/kg²)(5.972 x 10²⁴ kg)(7.348 x 10²² kg)/(8.098 x 10⁶ m)²

= (6.67 · 5.972 · 7.348 / 8.098²) · (10²³) Newtons

= (I get ...)

**4.463 x 10²³ Newtons**

That's almost exactly 10²³ pounds

= 50,153,000,000,000,000,000 tons.

Those are big numbers.

All I can say is: I wouldn't exactly call that "resting" on the surface".

#3 is a true statement whenever the bowling ball

and the golf ball are both on the same planet.

As per the question Jerome places a bag of flour on a scale.

The scale shows a weight of 17 N.

As per Newton's third law of motion for every action ,there is an equal and opposite reaction which is a fundamental role of physics.

Whenever the bag will be placed on the scale, the bag will push the scale downward with a force equal to its weight. As per Newton's third law the scale will also provide same amount of force in vertical upward direction which is also the normal reaction of the bag.

Here the weight of bag is 17 N which is the action. Hence the the reaction is also 17 N which is in vertically upward direction.

Hence the option A is correct

The

Apparent weight = *assumption: the raft is floating so, therefore, it is zero

for Fbuoyant let us use this equation to solve the problem

Fbuoyant= -density x volume x gravity

= - 650 x 24 x -9.81 =

__So the answer is__

**I hope my answer helped you.**

153,036 Kgms^-2

153,036 Kgms^-2

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D. The net gravitational force on the astronaut is not balanced by a normal force

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So, for this problem, we need to keep in mind what the formula for calculating mass is in the case of given acceleration and weight.

W=Weight

a=acceleration (gravitational pull)

m=mass

W=am, so

m=W/a.

Lets go through the answers:

A is incorrect right off the bat, since it's impossible for there to be circumstances that allow for both weight and mass to be equal.

B sounds like the right one to me, as the weight will affect the mass directly if the acceleration doesn't change (which is why they made it known that this was from one location), and vice versa.

C isn't correct, since it's basically saying the opposite of what actually happens occurs (weight goes up, mass goes down, and vice versa).

D has also been disproven based on our formula above. Weight is the one that equals mass times acceleration, not the other way around.

I hope this helps you out! Feel free to ask me any additional questions if you have any. :-)

**Answer:**

Option A, B, D and E are the characteristics of Metal

**Explanation:**

Some of the common characteristics of most of the metals are -

a) Most of the metal have lustrous surface which means they glitter in the presence of light for example - Iron, copper etc.

b) All metals are malleable which means they can be molded into different shape on beating for example copper can be converted into copper wire, jug, plates etc.

c) All metals are good carrier of charge and thus they are good conductors. These metals have valence shells electron which are free to move with a small force. Good metal conductors are copper , iron etc

d) Most of the metal are solid at room temperature.

What is the atomic weight of Fe2 O3

A weightlifter liftsa 1,250-N barbell 2 m in 3 s. how much power was used to lift the barbell?

P = 1,250 * 2/3

P = 2,500/3

P = 833.33 Watts

So, your final answer is 833.33 Watts