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# What are the characteristics of weight

Shape or texture...im just try....

## Related Questions

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Please help! Find the tension in each cord in the figure if the weight of the suspended object is w = 210N A) Find the tension in the cord A for system (b). B) Find the tension in the cord B for system (b).

We have to solve the system of equations:
- T a * cos 60° + T b * sin 45° - 210 N = 0
- T a * sin 60° + Tb cos 45° =  0
------------------------------------------------------
- 1/2 T a + √2 / 2 T b = 210 N
- √3 / 2 T a + √ 2 / 2 T b = 0     / * ( - 1 )
---------------------------------------------------
- 1/2 T a + √2 / 2 T b = 210 N
√ 3 / 2 T a - √2 / 2 T b = 0
----------------------------------------
T a ( √3 / 2 - 1 / 2 ) = 210 N
0.366 T a = 210 N
T a = 210 N : 0.366
1 ) T a = 573.77 N
Ta * √3 / 2 = T b * √ 2 / 2
T b = ( 573.77 * 1.732 ) : 1.4142
2 ) T b = 702.7 N

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The acceleration due to gravity on Earth is 9.80 m/s2. An African elephant can have a mass up to 6,050 kg. What is its weight?

The weight on earth is equal to m*g, where m is the mass and g is the gravitational force. 6050 (m) * 9.8 (g) = 59290 Newtons.

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Which of the following accurately shows how to calculate the weight of a 20kg object 20kgx9.8m/s 20kg/mass of the earth 20kg/9.8m/s 20kgxmass of the earth

The answer to your question is "20kgx9.8m/s" because weight is the force an object is exerting on another object, and the formula used to calculate force is Force = Mass * Acceleration.

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Use your data (attachment) from Part 3 and Newton’s laws to explain why the force meter measures a force if the cart is moving at a constant velocity. You should cover the following points. State Newton’s first law. • Identify the forces acting on the cart. • Describe the relationships between applied force and mass and between applied force and weight as linear (from data or mathematical derivation by applying Newton’s first law). • Explain why the data are linear in terms of Newton’s first law. • Graph F versus mass + cart.

The cart experiences a frictional force which is directly proportional to its weight. This means that there must be a force applied on the car to balance the forces on the car to produce a net force of 0.
This is in accordance to Newton's first law which states that an object at rest will remain at rest and an object in motion will remain in motion unless an external force acts on it. The force must be a resultant force.
Therefore, the force needed increases with the total weight of the cart as well as with the added mass in a linear manner.

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A construction worker with a weight of 850 N stands on a roof that is sloped at 20. What is the magnitude of the normal force of the roof on the worker?

Explanation:

Given that,

Force of gravity acting on the person, F = mg = 850 N

The roof is on the 20 degrees slope with the surface. We need to find the magnitude of normal force of the roof on the worker. It can be calculated as :   So, the normal force of the roof on the worker is 798.73 N. Hence, this is the required solution.

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What is the approximate weight of a 20-kg cannonball on Earth? 2 N 20 N 196 N 1,960 N

Weight of the cannonball, W = 196 N

Explanation:

Mass of the cannonball, m = 20 kg

We need to find its weight on earth. The weight of an object on the earth can be calculated by the product of mass and acceleration due to gravity as :  W = 196 N

So, the weight of the cannonball on the Earth's surface is 196 N. Hence, this is the required solution.

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What would be the weight of the moon if it were resting on the surface of the earth

We need to be careful here.
The calculation of the gravitational force between two objects
refers to the distance between their centers.
The minimum possible distance between the Earth's and moon's

Earth's radius . . . . .  6,360 km  =  6.36 x 10⁶ meters
Moon's radius . . . . .  1,738 km  =  1.738 x 10⁶ meters
Sum of their radii  =                      8.098 x 10⁶ meters

Also:
Earth's mass . . . . .  5.972 x 10²⁴ kg
Moon's mass . . . . .  7.348 x 10²²  kg

and now we're ready to go !

Gravitational force =

G  M₁ M₂ / R²

= (6.67 x 10⁻¹¹ N-m²/kg²)(
5.972 x 10²⁴ kg)(7.348 x 10²²  kg)/(8.098 x 10⁶ m)²

= (6.67 · 5.972 · 7.348 / 8.098²) · (10²³)      Newtons

=    (I get ...)        4.463 x 10²³ Newtons

That's almost exactly   10²³ pounds

=  50,153,000,000,000,000,000 tons.

Those are big numbers.
All I can say is:  I wouldn't exactly call that "resting" on the surface".

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Jerome places a bag of flour on a scale. The scale shows that the bag has a weight of 17 N. Which is the reaction force of the bag sitting on the scale? A. The scale exerts a 17 N force up on the bag. B. The scale exerts a 17 N force down on the counter. C. Earth exerts a 17 N force down on the bag. D. The bag exerts a 17 N force down on the scale.

As per the question Jerome places a bag of flour on a scale.

The scale shows a weight of 17 N.

As per Newton's third law of motion for every action ,there is an equal and opposite reaction which is a fundamental role of physics.

Whenever the bag  will be placed on the scale, the bag will push the scale downward with a force equal to its weight. As per Newton's third law the scale will also provide same amount of force in vertical upward direction which is also the normal reaction of the bag.

Here the weight of bag is 17 N which is the action. Hence the the reaction is also 17 N which is in vertically upward direction.

Hence the option A is correct

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A raft is made of plastic block with a density of 650kg/m3, and its dimensions are 2.00m x 3.00m x 5.00 m. What is the rafts apparent weight in water and the buoyant force on the raft in the water?

For the answer to the question above
The

Apparent weight = *assumption: the raft is floating so, therefore, it is zero

for Fbuoyant let us use this equation to solve the problem
Fbuoyant= -density x volume x gravity
= - 650 x 24 x -9.81 =
153,036 Kgms^-2
I hope my answer helped you.

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You pull upward on a stuffed suitcase with a force of 105N , and it accelerates upward at 0.710m/s2, what is the wieght and mass of the suitcase? Suppose the suitcase is on a rocket. The rocket launches with an acceleration of 29.0m/s2, What is the apparent weight of an 86-kg astronaut aboard this rocket?

I will assume the value of gravitational acceleration is 10m/s^-2 towards the centre of Earth.   ## Use our writing service to score better and meet your deadlines

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If you carry out an experiment measuring the weight and mass of objects in one particular location on the earth, what relation will you find between weight and mass in your measurements? A. They are equal. B. Weight is directly proportional to mass. C.Weight is inversely proportional to mass. D. Mass equals weight times acceleration due to gravity.

Hey there! Hello!

So, for this problem, we need to keep in mind what the formula for calculating mass is in the case of given acceleration and weight.

W=Weight
a=acceleration (gravitational pull)
m=mass

W=am, so
m=W/a.

A is incorrect right off the bat, since it's impossible for there to be circumstances that allow for both weight and mass to be equal.

B sounds like the right one to me, as the weight will affect the mass directly if the acceleration doesn't change (which is why they made it known that this was from one location), and vice versa.

C isn't correct, since it's basically saying the opposite of what actually happens occurs (weight goes up, mass goes down, and vice versa).

D has also been disproven based on our formula above. Weight is the one that equals mass times acceleration, not the other way around.

I hope this helps you out! Feel free to ask me any additional questions if you have any. :-)

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Which statements describe characteristics of most metals? Check all that apply. A They can be formed into wires. B They are shiny. C They are liquid at room temperature. D They are good conductors. can be easily shaped by hammering or pounding.

Option A, B, D and E are the characteristics of Metal

Explanation:

Some of the common characteristics of most of the metals are -

a) Most of the metal have lustrous surface which means they glitter in the presence of light for example - Iron, copper etc.

b) All metals are malleable which means they can be molded into different shape on beating for example copper can be converted into copper wire, jug, plates etc.

c) All metals are good carrier of charge and thus they are good conductors. These metals have valence shells electron which are free to move with a small force. Good metal conductors are copper , iron etc

d) Most of the metal are solid at room temperature.

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What is the atomic weight of Fe2 O3

159.69g/mol Because you can covert and you also learn in science class

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A weightlifter liftsa 1,250-N barbell 2 m in 3 s. how much power was used to lift the barbell?

Power = Force * Distance/ time
P = 1,250 * 2/3
P = 2,500/3
P = 833.33 Watts