## Related Questions

. How much work in joules is done by a person who uses a force of 25 N to move a desk 3.0 m?

here, F = 25 N

s = 3 m

Substitute it into the expression,

W = 25 * 3

W = 75 Joule

**So, your final answer is 75 J**

Hope this helps!

- T a * cos 60° + T b * sin 45° - 210 N = 0

- T a * sin 60° + Tb cos 45° = 0

------------------------------------------------------

- 1/2 T a + √2 / 2 T b = 210 N

- √3 / 2 T a + √ 2 / 2 T b = 0 / * ( - 1 )

---------------------------------------------------

- 1/2 T a + √2 / 2 T b = 210 N

√ 3 / 2 T a - √2 / 2 T b = 0

----------------------------------------

T a ( √3 / 2 - 1 / 2 ) = 210 N

0.366 T a = 210 N

T a = 210 N : 0.366

**1 )**

**T a = 573.77 N**

Ta * √3 / 2 = T b * √ 2 / 2

T b = ( 573.77 * 1.732 ) : 1.4142

**2 )**

**T b = 702.7 N**

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But if he passed high school physics, then he may remember that

'work' in physics means (force) x (distance). If there's no distance,

then there's no work.

He realizes that he isn’t doing any work because he's not moving the weight.

Answer: It increases the time it takes for the person to stop.

Explanation:

From Newton's second law of motion, we know that the **force is equal to rate of change of momentum. **

In a car, during collision when the air bag pops out, **it increases the time it takes to stop** the person thereby** decreasing the rate of change of momentum**. Hence, the force acting on the person minimizes.

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How much force is needed to stop an 80kg football player if he decelerates at 5m/s2

This can be solve using newtons second law of motion

F = ma

Where F is the force applied

M is the mass

A is the acceleration

Substituting the given values

F = ma

F = ( 80 kg ) ( 5 m/s2)

F = 400 N of force needed

*Force = Mass * Acceleration*.

**Answer:**

ITS NONE

**Explanation:**

This is in accordance to Newton's first law which states that an object at rest will remain at rest and an object in motion will remain in motion unless an external force acts on it. The force must be a resultant force.

Therefore, the force needed increases with the total weight of the cart as well as with the added mass in a linear manner.

Explanation:

Given that,

Force of gravity acting on the person, F = mg = 850 N

The roof is on the 20 degrees slope with the surface. We need to find the magnitude of normal force of the roof on the worker. It can be calculated as :

So, the normal force of the roof on the worker is 798.73 N. Hence, this is the required solution.

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If gravitational pull got three times stronger what happens to your weight?

it would be 32newtons

20 kg*1.6 m/s²=32 N

What is the approximate weight of a 20-kg cannonball on Earth? 2 N 20 N 196 N 1,960 N

**Answer:**

Weight of the cannonball, W = 196 N

**Explanation:**

Mass of the cannonball, m = 20 kg

We need to find its weight on earth. The weight of an object on the earth can be calculated by the product of mass and acceleration due to gravity as :

W = 196 N

**So, the weight of the cannonball on the Earth's surface is 196 N. Hence, this is the required solution.**

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What would be the weight of the moon if it were resting on the surface of the earth

The calculation of the gravitational force between two objects

refers to the distance between their centers.

The minimum possible distance between the Earth's and moon's

centers is the sum of their radii (radiuses).

Earth's radius . . . . . 6,360 km = 6.36 x 10⁶ meters

Moon's radius . . . . . 1,738 km = 1.738 x 10⁶ meters

Sum of their radii = 8.098 x 10⁶ meters

Also:

Earth's mass . . . . . 5.972 x 10²⁴ kg

Moon's mass . . . . . 7.348 x 10²² kg

and now we're ready to go !

Gravitational force =

G M₁ M₂ / R²

= (6.67 x 10⁻¹¹ N-m²/kg²)(5.972 x 10²⁴ kg)(7.348 x 10²² kg)/(8.098 x 10⁶ m)²

= (6.67 · 5.972 · 7.348 / 8.098²) · (10²³) Newtons

= (I get ...)

**4.463 x 10²³ Newtons**

That's almost exactly 10²³ pounds

= 50,153,000,000,000,000,000 tons.

Those are big numbers.

All I can say is: I wouldn't exactly call that "resting" on the surface".

#3 is a true statement whenever the bowling ball

and the golf ball are both on the same planet.

As per the question Jerome places a bag of flour on a scale.

The scale shows a weight of 17 N.

As per Newton's third law of motion for every action ,there is an equal and opposite reaction which is a fundamental role of physics.

Whenever the bag will be placed on the scale, the bag will push the scale downward with a force equal to its weight. As per Newton's third law the scale will also provide same amount of force in vertical upward direction which is also the normal reaction of the bag.

Here the weight of bag is 17 N which is the action. Hence the the reaction is also 17 N which is in vertically upward direction.

Hence the option A is correct

The

Apparent weight = *assumption: the raft is floating so, therefore, it is zero

for Fbuoyant let us use this equation to solve the problem

Fbuoyant= -density x volume x gravity

= - 650 x 24 x -9.81 =

__So the answer is__

**I hope my answer helped you.**

153,036 Kgms^-2

153,036 Kgms^-2

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Agility refers to a persons level of flexibility true or false

D. The net gravitational force on the astronaut is not balanced by a normal force