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# What is the weight of a person with a massa of 80kg

784 Newtons or 176.37 lbs

## Related Questions

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What are the characteristics of weight

Shape or texture...im just try....

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. How much work in joules is done by a person who uses a force of 25 N to move a desk 3.0 m?

We Know, W = F * s
here, F = 25 N
s = 3 m

Substitute it into the expression,
W = 25 * 3
W = 75 Joule

Hope this helps!

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Please help! Find the tension in each cord in the figure if the weight of the suspended object is w = 210N A) Find the tension in the cord A for system (b). B) Find the tension in the cord B for system (b).

We have to solve the system of equations:
- T a * cos 60° + T b * sin 45° - 210 N = 0
- T a * sin 60° + Tb cos 45° =  0
------------------------------------------------------
- 1/2 T a + √2 / 2 T b = 210 N
- √3 / 2 T a + √ 2 / 2 T b = 0     / * ( - 1 )
---------------------------------------------------
- 1/2 T a + √2 / 2 T b = 210 N
√ 3 / 2 T a - √2 / 2 T b = 0
----------------------------------------
T a ( √3 / 2 - 1 / 2 ) = 210 N
0.366 T a = 210 N
T a = 210 N : 0.366
1 ) T a = 573.77 N
Ta * √3 / 2 = T b * √ 2 / 2
T b = ( 573.77 * 1.732 ) : 1.4142
2 ) T b = 702.7 N

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The acceleration due to gravity on Earth is 9.80 m/s2. An African elephant can have a mass up to 6,050 kg. What is its weight?

The weight on earth is equal to m*g, where m is the mass and g is the gravitational force. 6050 (m) * 9.8 (g) = 59290 Newtons.

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In a car, how does an air bag minimize the force acting on a person during a collision? It increases the change in momentum of the person. It decreases the change in momentum of the person. It increases the time it takes for the person to stop. It decreases the time it takes for the person to stop.

Answer: It increases the time it takes for the person to stop.

Explanation:

From Newton's second law of motion, we know that the force is equal to rate of change of momentum.

In a car, during collision when the air bag pops out, it increases the time it takes to stop the person thereby decreasing the rate of change of momentum. Hence, the force acting on the person minimizes.

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How much force is needed to stop an 80kg football player if he decelerates at 5m/s2

This can be solve using newtons second law of motion

F = ma

Where F is the force applied

M is the mass

A is the acceleration

Substituting the given values

F = ma

F = ( 80 kg ) ( 5 m/s2)

F = 400 N of force needed

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Which of the following accurately shows how to calculate the weight of a 20kg object 20kgx9.8m/s 20kg/mass of the earth 20kg/9.8m/s 20kgxmass of the earth

The answer to your question is "20kgx9.8m/s" because weight is the force an object is exerting on another object, and the formula used to calculate force is Force = Mass * Acceleration.

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Use your data (attachment) from Part 3 and Newton’s laws to explain why the force meter measures a force if the cart is moving at a constant velocity. You should cover the following points. State Newton’s first law. • Identify the forces acting on the cart. • Describe the relationships between applied force and mass and between applied force and weight as linear (from data or mathematical derivation by applying Newton’s first law). • Explain why the data are linear in terms of Newton’s first law. • Graph F versus mass + cart.

The cart experiences a frictional force which is directly proportional to its weight. This means that there must be a force applied on the car to balance the forces on the car to produce a net force of 0.
This is in accordance to Newton's first law which states that an object at rest will remain at rest and an object in motion will remain in motion unless an external force acts on it. The force must be a resultant force.
Therefore, the force needed increases with the total weight of the cart as well as with the added mass in a linear manner.

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A construction worker with a weight of 850 N stands on a roof that is sloped at 20. What is the magnitude of the normal force of the roof on the worker?

Explanation:

Given that,

Force of gravity acting on the person, F = mg = 850 N

The roof is on the 20 degrees slope with the surface. We need to find the magnitude of normal force of the roof on the worker. It can be calculated as :

So, the normal force of the roof on the worker is 798.73 N. Hence, this is the required solution.

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What is the approximate weight of a 20-kg cannonball on Earth? 2 N 20 N 196 N 1,960 N

Weight of the cannonball, W = 196 N

Explanation:

Mass of the cannonball, m = 20 kg

We need to find its weight on earth. The weight of an object on the earth can be calculated by the product of mass and acceleration due to gravity as :

W = 196 N

So, the weight of the cannonball on the Earth's surface is 196 N. Hence, this is the required solution.

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What would be the weight of the moon if it were resting on the surface of the earth

We need to be careful here.
The calculation of the gravitational force between two objects
refers to the distance between their centers.
The minimum possible distance between the Earth's and moon's

Earth's radius . . . . .  6,360 km  =  6.36 x 10⁶ meters
Moon's radius . . . . .  1,738 km  =  1.738 x 10⁶ meters
Sum of their radii  =                      8.098 x 10⁶ meters

Also:
Earth's mass . . . . .  5.972 x 10²⁴ kg
Moon's mass . . . . .  7.348 x 10²²  kg

and now we're ready to go !

Gravitational force =

G  M₁ M₂ / R²

= (6.67 x 10⁻¹¹ N-m²/kg²)(
5.972 x 10²⁴ kg)(7.348 x 10²²  kg)/(8.098 x 10⁶ m)²

= (6.67 · 5.972 · 7.348 / 8.098²) · (10²³)      Newtons

=    (I get ...)        4.463 x 10²³ Newtons

That's almost exactly   10²³ pounds

=  50,153,000,000,000,000,000 tons.

Those are big numbers.
All I can say is:  I wouldn't exactly call that "resting" on the surface".

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Jerome places a bag of flour on a scale. The scale shows that the bag has a weight of 17 N. Which is the reaction force of the bag sitting on the scale? A. The scale exerts a 17 N force up on the bag. B. The scale exerts a 17 N force down on the counter. C. Earth exerts a 17 N force down on the bag. D. The bag exerts a 17 N force down on the scale.

As per the question Jerome places a bag of flour on a scale.

The scale shows a weight of 17 N.

As per Newton's third law of motion for every action ,there is an equal and opposite reaction which is a fundamental role of physics.

Whenever the bag  will be placed on the scale, the bag will push the scale downward with a force equal to its weight. As per Newton's third law the scale will also provide same amount of force in vertical upward direction which is also the normal reaction of the bag.

Here the weight of bag is 17 N which is the action. Hence the the reaction is also 17 N which is in vertically upward direction.

Hence the option A is correct

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A raft is made of plastic block with a density of 650kg/m3, and its dimensions are 2.00m x 3.00m x 5.00 m. What is the rafts apparent weight in water and the buoyant force on the raft in the water?

For the answer to the question above
The

Apparent weight = *assumption: the raft is floating so, therefore, it is zero

for Fbuoyant let us use this equation to solve the problem
Fbuoyant= -density x volume x gravity
= - 650 x 24 x -9.81 =
153,036 Kgms^-2
I hope my answer helped you.

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Agility refers to a persons level of flexibility true or false

Your answer would be false, it's in the sentence that agility and flexibility are two different things. Hope this helps!

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